EMA 8 and 21 crossover scan help needed
Comments
-
The second parts are easy
and [close > 30]
and [sma(?, volume) > 500000] // you decide length of MA where ? is
Then you have to decide the direction of the crossover. MA 8 is faster, so it will always do the crossing, but there is no "cross below" operator, only "x", which is "cross above"
So for 8 crosses above 21
and [ema(8,close) x ema(21,close)]
but for 8 crosses below 21, you have to write it as if 21 crosses above 8, so:
and [ema(21,close) x ema(8, close)]0
Categories
- All Categories
- 2.4K StockCharts
- 397 SharpCharts
- 146 Other Charting Tools
- 69 Saved Charts and ChartLists
- 1.5K Scanning
- 74 Data Issues
- 177 Other StockCharts Questions
- 224 Technical Analysis
- 155 Using Technical Analysis
- 6 InterMarket and International
- 19 Market and Breadth Indicators
- 44 Market Analysis
- 109 Trading
- 109 Trading Strategies
- 162 S.C.A.N the StockCharts Answer Network forum
- 64 Using this StockCharts Answer Network forum
- 98 s.c.a.n. archives
- 7 Off-Topic
- 7 The Cogitation & Rumination Emporium
- Forum Test Area
